The solution is a bounded interval of width 10, centered at x = 3.
Any x between -2 and 8 (inclusive based on your sign) makes |x - 3| < 5 true.
For "less than" absolute value inequalities the solution is always a bounded AND interval, meaning x is squeezed between two values.
In interval notation: (-2, 8).
Next stepTo verify your answer, pick a test value from inside the solution region and confirm it satisfies the original inequality, then pick one outside and confirm it does not.