Standard deviation of the sampling distribution: SE = σ / sqrt(n)
Mean of sampling distribution (μ_x-bar)50
Z-score2.1909
Probability98.5770%
2.190998.6% below · z
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P(X-bar <= 54) = 98.5770%
The sampling distribution of the mean has a standard error of 1.8257, which is 10 / sqrt(30). With a larger sample the curve narrows proportionally.
With n = 30 (>= 30) the CLT guarantees the sampling distribution is approximately normal regardless of the population shape.
The sample mean 54 corresponds to a z-score of 2.1909, which is 2.19 standard errors above the population mean.
Doubling the sample size reduces the standard error by a factor of sqrt(2) (about 29%), so collecting more data is a powerful way to tighten the sampling distribution.
Next stepUse these results to construct a confidence interval (add/subtract z * SE from the sample mean) or to set a decision threshold for a hypothesis test.