Wheatstone Bridge Calculator

Your details

Balanced mode solves for the fourth resistor that brings the bridge to null. Unbalanced mode computes the differential voltage across the detector terminals.
Resistance of the upper-left arm (between supply positive and the junction leading to the detector).
Ohm
Resistance of the lower-left arm (between the junction and supply negative/ground).
Ohm
Resistance of the upper-right arm (the known ratio arm).
Ohm
The DC voltage applied across the bridge (from the top node to the bottom node). Required for output voltage and current calculations.
V
Result
3,000

Rx (balanced) or Vout (unbalanced) depending on the selected mode

Unknown resistance (Rx)3,000Ohm
Equivalent resistance (Req)1,800Ohm
Supply current2.778mA
Bridge sensitivity0mV/V
Equiv. resistance (Ohm)1,800
Supply current (mA)2.778

Rx = 3000.000 Ohm balances this bridge.

  • The bridge balances when Rx is 3000.00 Ohm, derived from the ratio R2/R1 = 2.0000.
  • The supply sees an equivalent load of 1800.0 Ohm (the two half-bridges in parallel).
  • At 5 V supply the total current drawn is 2.78 mA.
  • At exact balance the galvanometer reads zero: any deviation of Rx from this value will produce a measurable output voltage.

Next stepUse the Unbalanced Bridge mode to see how much voltage the detector sees when Rx deviates from this null point.

 = Powered by OnlyCalculators