Heat Capacity Calculator

Your details

Pick the quantity you want to find. The other three fields become the known inputs.
Choosing a preset fills in specific heat automatically. Switch to Custom to enter your own value.
Leave this blank when solving for Q; it is computed for you.
Mass of the sample being heated or cooled.
The rise (positive) or drop (negative) in temperature.
Auto-filled from the material preset. Switch substance to Custom to enter your own value.
J/(kg·K)
Result
4,186

The solved value in your chosen units.

Quantity solvedHeat energy (Q) in J
Heat capacity of sample (C = mc)4,186J/K
Specific heat (c)4,186J/(kg·K)
Heat energy (J)4,186J
Heat energy (J)4,186
Heat capacity of sample (J/K)4,186

Heating Water (15 °C) requires 4186.00 J.

  • The heat capacity of your sample is 4186.0 J/K, meaning it absorbs 4186.0 joules for every 1 Kelvin (or 1 degree Celsius) rise.
  • Water (15 °C) has a high specific heat (4186 J/(kg*K)), which means it resists temperature change well - useful for thermal storage or cooling systems.
  • The heat transferred (4186 J) is equivalent to about 1.16 watt-hours of electrical energy.

Next stepPair this result with a heat transfer rate (watts) to find how long heating or cooling will take: time (s) = Q (J) / power (W).

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