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Condense Logarithms Calculator

Enter two logarithmic terms and choose whether to add or subtract them. This calculator applies the product rule, quotient rule, or power rule to write the expanded form as one single logarithm, then evaluates it numerically. The step-by-step panel shows exactly how each rule works with your numbers.

Your details

Choose the type of expression to condense.
The shared base of both logarithms. Common choices: 2, e (use 2.718), 10.
The number multiplied by the first logarithm. Becomes the exponent via the power rule.
The argument of the first logarithm. Must be positive.
The number multiplied by the second logarithm.
The argument of the second logarithm. Must be positive.
Numeric result
3.54741

Numerical value of the condensed logarithm

Condensed argument576
Condensed expressionlog_6(576)
Original expression3 * log_6(4) + 1 * log_6(9)

Condensed: 3 * log_6(4) + 1 * log_6(9) = log_6(576) = 3.54741

  • The condensed form is log_6(576), which equals approximately 3.54741.
  • The argument inside the condensed logarithm is 576.
  • You can verify the answer by expanding it back: raise the base to the numeric result and check that it equals the condensed argument.

Next stepTo expand a logarithm (reverse this process), use the product, quotient, and power rules in the forward direction, splitting a single log into a sum or difference of logs.

Formula

Power: xlogb(a)=logb(ax)Product: logb(A)+logb(B)=logb(AB)Quotient: logb(A)logb(B)=logb ⁣(AB)\text{Power: } x \cdot \log_b(a) = \log_b(a^x) \\ \text{Product: } \log_b(A) + \log_b(B) = \log_b(A \cdot B) \\ \text{Quotient: } \log_b(A) - \log_b(B) = \log_b\!\left(\tfrac{A}{B}\right)

Worked example

Condense 3 * log_6(4) + log_6(9). Step 1: power rule gives log_6(4^3) + log_6(9^1) = log_6(64) + log_6(9). Step 2: product rule gives log_6(64 * 9) = log_6(576). Step 3: evaluate: log_6(576) = ln(576)/ln(6) ≈ 3.547.

What does it mean to condense a logarithm?

Condensing a logarithm means rewriting a sum, difference, or multiple of logarithmic expressions as a single logarithm. For example, 3 * log_6(4) + log_6(9) can be condensed to log_6(576). This is the reverse of expanding logarithms, and it relies on three fundamental properties that hold whenever the base b is positive and not equal to 1, and all arguments are positive numbers.

The three rules are:

  • Power rule: x * log_b(a) = log_b(a^x) - the coefficient becomes an exponent on the argument.
  • Product rule: log_b(A) + log_b(B) = log_b(A * B) - a sum of logs becomes the log of a product.
  • Quotient rule: log_b(A) - log_b(B) = log_b(A / B) - a difference of logs becomes the log of a quotient.
When terms have coefficients, you apply the power rule first to clear the coefficients, then apply the product or quotient rule to merge the two resulting logs into one.

How to use this calculator

Select the operation: addition for the product rule, subtraction for the quotient rule, or "power rule only" if you have a single term with a coefficient. Enter the base shared by both logarithms (use 10 for common logarithms, 2.718 for natural logarithms, or any valid base), then enter the coefficient and argument of each term. The calculator instantly shows the condensed expression in symbolic form, the numeric value, and a step-by-step breakdown.

The default example condenses 3 * log_6(4) + log_6(9) into log_6(576) ≈ 3.547, which is a classic textbook problem demonstrating both the power and product rules in one calculation.

Why condensing logarithms matters in algebra and beyond

Condensing logarithms is a core algebraic skill used when solving logarithmic equations, simplifying expressions before differentiation or integration, and working with information-theoretic formulas in computer science. In information theory, the entropy formula H = -sum p_i * log(p_i) benefits from condensing properties when simplifying mutual information calculations. In chemistry, the Henderson-Hasselbalch equation pH = pKa + log([A-]/[HA]) can be derived by condensing a difference of logs. Scientists and engineers also use condensing when fitting exponential models, because taking the log of a product turns multiplication into addition, which is far easier to work with in regression.

Understanding condensation also makes it easier to spot errors: if you see two log terms added together and they share the same base, you can immediately collapse them into one log of a product. That recognition speeds up equation solving considerably.

Common mistakes and edge cases

Several errors come up repeatedly when condensing logarithms:

  • Negative or zero arguments: log_b(x) is undefined for x <= 0. If the quotient rule gives a^x / c^y <= 0, the condensed form does not exist over the real numbers.
  • Forgetting the power rule first: you cannot directly apply the product rule to 3 * log(4) + log(9) - you must first convert to log(64) + log(9), then apply the product rule to get log(576).
  • Different bases: the product and quotient rules require both logarithms to share the same base. If the bases differ, you must use the change-of-base formula to convert them first.
  • Treating addition of arguments as multiplication: log_b(a) + log_b(c) = log_b(a * c), not log_b(a + c). The log of a sum has no simple condensed form.

Logarithm condensation rules at a glance

Rule nameExpanded formCondensed formKey condition
Power rulex * log_b(a)log_b(a^x)b > 0, b != 1, a > 0
Product rulelog_b(A) + log_b(B)log_b(A * B)A > 0, B > 0
Quotient rulelog_b(A) - log_b(B)log_b(A / B)A > 0, B > 0
Combined (add)x*log_b(a) + y*log_b(c)log_b(a^x * c^y)All arguments positive
Combined (subtract)x*log_b(a) - y*log_b(c)log_b(a^x / c^y)a^x / c^y > 0

The three rules used to condense expanded logarithmic expressions into a single log.

Frequently asked questions

What is the power rule for logarithms?

The power rule states that x * log_b(a) = log_b(a^x). The coefficient in front of a logarithm can be moved inside as an exponent on the argument. For example, 3 * log_6(4) = log_6(4^3) = log_6(64). This rule is always the first step when condensing expressions that have coefficients.

How do you condense log_6(4) + log_6(9)?

Apply the product rule: log_b(A) + log_b(B) = log_b(A * B). So log_6(4) + log_6(9) = log_6(4 * 9) = log_6(36). Since 6^2 = 36, the result equals exactly 2.

Can you condense logarithms with different bases?

Not directly. The product and quotient rules only work when both logarithms share the same base. If the bases differ, convert one or both using the change-of-base formula: log_b(x) = log_c(x) / log_c(b), where c is any convenient base (usually 10 or e). Then both terms share a common base and you can condense normally.

What happens when the condensed argument is 1?

When the condensed argument equals 1, the result is always 0, because any base raised to the power 0 equals 1: log_b(1) = 0 for all valid bases. This happens, for example, when x * log_b(a) - x * log_b(a) = log_b(a^x / a^x) = log_b(1) = 0.

How do you verify a condensed logarithm is correct?

Raise the base to the numeric result and check that it equals the condensed argument. For example, if you condensed an expression to log_6(576) ≈ 3.547, verify by computing 6^3.547 and confirming it is approximately 576. You can also expand the condensed form back using the product and power rules and check it matches the original expression.

What is the quotient rule for logarithms?

The quotient rule states that log_b(A) - log_b(B) = log_b(A / B). A difference of two logarithms with the same base condenses to the logarithm of their quotient. For example, log_2(16) - log_2(4) = log_2(16/4) = log_2(4) = 2.

Can the condensed logarithm be negative?

Yes. A negative result simply means the condensed argument is between 0 and 1 (a positive fraction). For instance, log_10(0.01) = -2 because 10^(-2) = 0.01. As long as the condensed argument is positive, the logarithm is defined and the result may be any real number.

Sources

Written by Dr. Rajiv Menon, PhD Applied Mathematician · Bengaluru, India

Applied mathematician bridging algebraic theory and computational tools for students, engineers, and everyday problem-solvers.

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