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Physics

Column Buckling Calculator (Euler and Johnson)

Enter your column dimensions, material, and end conditions to find the critical buckling load. The calculator automatically picks Euler's formula for slender columns and Johnson's formula for intermediate columns based on the slenderness ratio. Switch between metric and imperial units. The show-your-work panel traces every step of the calculation.

Your details

Switches length and force units across all inputs and outputs.
How the column ends are restrained. This determines the effective-length factor K.
Actual unsupported length of the column.
mm
Second moment of area about the weak axis. For a 100x100 mm square: I = 100^4 / 12 = 8,333,333 mm^4.
mm⁴
Total cross-sectional area of the column. Used to compute radius of gyration and Johnson formula.
mm²
Select a preset material or choose Custom to enter your own E and yield stress.
Elastic modulus of the column material. Auto-filled when a preset material is chosen.
MPa
Compressive yield strength of the material. Used by the Johnson formula for intermediate columns.
MPa
The allowable load is the critical load divided by this factor. Typical structural design uses 2 to 4.
Critical buckling load (Pcr)Slender column - Euler governs
411.23

The axial load at which the column buckles (Euler or Johnson formula applied automatically).

Pcr unitkN
Allowable load (Pa)137.08
Slenderness ratio (S)219.1
Critical slenderness ratio (Sc)125.7
Radius of gyration (r)9.129
Effective length (Le)2,000
Formula usedEuler
Column classSlender (long column)
219.1
Very short strut<10Intermediate (Johnson)10-80Slender (Euler)80-160Very slender160+
01k2k15030756000
Column length L (mm)
  • Johnson (intermediate)
  • Euler (slender)

Critical buckling load: 411.23 kN (Euler formula, Slender (long column)).

  • The Euler formula was applied because the slenderness ratio (219.1) is above the critical slenderness ratio (125.7).
  • At the critical load of 411.23 kN, the column will suddenly deflect sideways. Any load beyond this is unsafe regardless of material strength.
  • The allowable load (137.08 kN) already includes your safety factor of 3. Keep the applied load below this value.

Next stepTo increase the critical load, consider increasing I (wider or thicker section), reducing the unsupported length, or adding intermediate bracing to change the effective length.

What is column buckling?

Buckling is a sudden lateral deflection that occurs when a slender structural member is compressed beyond its critical load. Unlike a simple compression failure where the material yields, buckling is an instability failure: the column snaps sideways before the material stress reaches yield strength. It is one of the most common failure modes in structural columns, struts, and machine shafts, and it governed by the geometry of the section and the column length rather than by raw material strength alone. Leonhard Euler derived the first mathematical treatment of buckling in 1744, and his formula remains the standard for long, slender columns today.

Euler vs. Johnson formula: which one applies?

The correct formula depends on the slenderness ratio S = Le / r, where Le is the effective length and r is the radius of gyration. The critical slenderness Sc = pi x sqrt(2E / sy) marks the boundary. When S is greater than or equal to Sc, the column is considered slender and Euler's formula applies: Pcr = pi^2 x E x I / Le^2. The critical load depends only on stiffness (E and I), not on strength. When S is less than Sc, the column is intermediate and Johnson's parabolic formula applies: Pcr = sy x A x [1 - (sy / (4 pi^2 E)) x S^2]. Here material yield strength matters, and the critical load is lower than the Euler prediction. Using the Euler formula below Sc would overestimate the critical load and give an unsafe result.

How to improve resistance to buckling

There are four practical levers. First, reduce the unsupported length by adding lateral bracing or intermediate supports - halving the length quadruples the Euler critical load. Second, choose a cross-section with a larger second moment of inertia about the weak axis: hollow sections and I-beams are far more efficient than solid rounds or squares of the same area. Third, change the end conditions: fixing both ends rather than pinning them halves the effective length and multiplies the critical load by four. Fourth, for intermediate columns, a higher yield-strength material increases the Johnson critical load directly. All four approaches can be combined and the effect is cumulative.

Units and sign conventions used here

In metric mode the calculator accepts length in millimetres, moment of inertia in mm^4, area in mm^2, and modulus and yield stress in MPa. The critical load is returned in kilonewtons. In imperial mode the inputs use inches, in^4, in^2, and psi; the output is in pound-force. Internally all calculations are carried out in SI (metres, Pascals, Newtons) and converted at the output stage. The safety factor is dimensionless and divides the critical load to give the allowable load.

End conditions and effective-length factors (K)

End conditionsTheoretical KDesign K (AISC)Buckled shape
Fixed - Fixed0.50.65Reverse S-curve
Fixed - Pinned0.70.80Single half-wave with offset
Pinned - Pinned1.01.00Single half-sine wave
Fixed - Guided1.01.20Quarter-wave (rotation fixed)
Fixed - Free (cantilever)2.02.10Quarter-wave (free tip)
Pinned - Guided2.02.00Half-wave with lateral offset

Theoretical K values. In practice, recommended design values are slightly higher to account for imperfect restraint.

Frequently asked questions

What is the difference between Euler and Johnson buckling formulas?

Euler's formula (Pcr = pi^2 E I / Le^2) applies to long, slender columns and predicts an elastic instability failure. It depends on stiffness, not strength. Johnson's formula (Pcr = sy A [1 - (sy / 4pi^2 E) S^2]) applies to intermediate columns where inelastic effects reduce the load below the Euler prediction. The slenderness ratio S relative to the critical slenderness Sc determines which formula governs: use Euler when S >= Sc, Johnson when S < Sc.

What is the effective length factor K?

K accounts for the boundary conditions at each end of the column. A pinned-pinned column buckles into a single half-sine wave and has K = 1. Fixing both ends halves the effective buckle length, so K = 0.5 and the critical load is four times higher. A cantilever (fixed-free) buckles as a quarter-wave, so K = 2 and is four times weaker than a pinned-pinned column of the same actual length. In real structures, connections are rarely perfect, so design codes recommend slightly larger K values than the theoretical ones.

What is the radius of gyration?

The radius of gyration r = sqrt(I / A) measures how spread out the cross-sectional area is from the centroidal axis. A large r means the area is far from the axis and the section resists buckling more effectively. Hollow sections and flanged shapes like I-beams have a larger r for a given area than solid rounds, which is why they are preferred in compression members.

What safety factor should I use for column buckling?

Structural design codes typically specify safety factors between 2 and 4 for buckling, compared to 1.5 to 2 for yielding, because buckling is a sudden collapse rather than a gradual yield. The American Institute of Steel Construction (AISC) uses an effective safety factor of about 1.67 applied to the nominal buckling strength in allowable stress design. Machine design texts often recommend 3 to 4 for columns subject to vibration or uncertain loading. The allowable load shown by this calculator is Pcr divided by the safety factor you enter.

Can this calculator be used for beam-columns or eccentric loads?

No. This calculator assumes a perfectly straight column with the load applied exactly at the centroid (concentric axial load). If the load is offset from the centroid (eccentric loading), or if the column also carries a transverse bending load, the secant formula or a combined bending-compression interaction check is needed. Most real-world columns have some eccentricity due to manufacturing tolerances and connection geometry, so the allowable load from this tool should be treated as an upper bound and an appropriate safety factor applied.

Sources

Written by Dr. Tomás Okafor, PhD Physicist · Lagos, Nigeria

Physicist specializing in classical mechanics, bringing 17 years of research and applied dynamics expertise to every calculator he reviews.

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