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Physics

Newton's Law of Cooling Calculator

Enter an initial temperature, ambient temperature, cooling constant and time to find the object's temperature at that moment. Switch to reverse mode to find how long cooling takes, or use the physical-properties panel to derive the cooling constant from heat-transfer coefficient, surface area, mass and specific heat. The cooling curve chart updates live.

Your details

Choose what to calculate: the temperature after a given time, how long cooling takes, or the cooling constant from physical properties.
The object temperature at time zero.
°C
The surrounding environment temperature (constant).
°C
The cooling rate constant (per unit time). Higher values mean faster cooling. Must match the selected time unit.
1/min
How long the object has been cooling.
min
Final temperature T(t)
62.46

Object temperature after the elapsed time

Temperature change-27.54
Half-life of temperature difference13.86
Cooling progress0.4%
Time to reach target-
Cooling constant k-
Cooling constant k (per min)-
0.4%
Just started<0.25Quarter cooled0.25-0.5Halfway0.5-0.75Near ambient0.75-0.95At ambient0.95+
0459003569
Time (min)
  • Object temperature
  • Ambient temperature

After the elapsed time the temperature is 62.46 °C.

  • The object is 39.3% of the way from its starting temperature to ambient.
  • The temperature gap halves every 13.86 min. After 10 half-lives the difference is less than 0.1% of the original.
  • At this moment the object is still 42.46 °C away from ambient temperature.
  • Newton's Law of Cooling assumes the temperature difference is small enough that radiative heat transfer is negligible and the ambient temperature stays constant.

Next stepTo speed cooling, increase air circulation (higher h) or increase the surface area exposed to the environment.

What is Newton's Law of Cooling?

Newton's Law of Cooling states that the rate at which an object loses heat to its surroundings is proportional to the temperature difference between the object and those surroundings. Mathematically, dT/dt = -k(T - T_amb), where T is the object temperature, T_amb is the fixed ambient temperature, and k is the cooling constant (a positive number, in units of inverse time). Solving this differential equation yields the exponential decay formula T(t) = T_amb + (T0 - T_amb) × e^(-kt), which gives the temperature at any time t. The law is an excellent approximation when the temperature difference is not too large and radiative heat transfer is small compared to convective and conductive losses.

How to use this calculator

Three solve modes are available. In the default mode, enter the starting temperature, ambient temperature, cooling constant k and elapsed time to find the temperature at that moment. Switch to "Time to reach target T" to enter the same parameters plus a desired final temperature and find how long cooling takes. The "Cooling constant k" mode derives k from physical properties: enter the heat transfer coefficient h, exposed surface area A, mass and specific heat, and the calculator computes k = hA / (mc_p), which you can then carry over to the other modes. The cooling curve chart updates with each change so you can see the full trajectory.

The cooling constant k and what affects it

The cooling constant k = hA / (mc_p), where h is the convective heat transfer coefficient, A is the exposed surface area, m is mass and c_p is specific heat. A high h (forced air, moving liquid) increases k and speeds cooling. A large surface area also increases k, which is why fins on a heat sink or a wider coffee mug cool faster. A larger mass or high specific heat reduces k because more energy must be transferred for the same temperature drop. Typical k values for a cup of coffee in still air are around 0.01 to 0.05 per minute, while a small electronic component being cooled by a fan might have k around 0.5 to 2 per minute.

Half-life and cooling progress

The half-life of the temperature gap is the time for (T - T_amb) to drop by half, and equals ln(2) / k. After one half-life, 50% of the gap remains; after two, 25%; after ten, less than 0.1%. This makes it easy to estimate when an object is "essentially" at ambient. For example, if k = 0.05 min^-1, the half-life is ln(2) / 0.05 = 13.9 minutes. After 70 minutes (five half-lives) the temperature difference is 1/32 of the original, meaning a coffee that started at 90 C in a 20 C room would be within about 2 C of room temperature.

Typical heat transfer coefficients (h) and cooling constants

Scenarioh (W/m²K)Cooling rate
Still air, small object5-10 Slow
Still air, large flat surface10-25 Moderate
Light forced air (fan)25-100 Fast
Strong forced air / wind100-300 Very fast
Still water immersion200-1000 Very fast
Flowing water1000-15000 Extremely fast
Boiling water2500-35000 Extremely fast

Approximate values for natural convection in still air. Forced convection (fans, liquid cooling) can be 10-100x higher.

Frequently asked questions

What is Newton's Law of Cooling formula?

The formula is T(t) = T_amb + (T0 - T_amb) × e^(-kt), where T(t) is the temperature after time t, T_amb is the ambient (surrounding) temperature, T0 is the initial temperature, k is the cooling constant and e is Euler's number (~2.71828). The formula comes from solving the differential equation dT/dt = -k(T - T_amb).

How do I find the cooling constant k?

You can derive k from physical properties: k = hA / (mc_p), where h is the heat transfer coefficient in W/(m²K), A is surface area in m², m is mass in kg and c_p is specific heat in J/(kg K). Alternatively, if you have two measured temperatures at known times, you can solve k = -ln[(T2 - T_amb) / (T1 - T_amb)] / (t2 - t1). This calculator's "Cooling constant k" mode does the first approach automatically.

What units should k be in?

k has units of inverse time, such as 1/s, 1/min or 1/hr. The value you use in the formula must match the time unit you plug in. If k = 0.05 min^-1, you must measure time in minutes. This calculator keeps the time unit consistent throughout, so switching between seconds, minutes and hours automatically rescales k.

When does Newton's Law of Cooling break down?

The law is an approximation that works well when the temperature difference between the object and surroundings is modest (typically under a few hundred degrees Celsius). At very high temperature differences, thermal radiation (which follows the Stefan-Boltzmann law, proportional to T^4) becomes significant, and the simple exponential model underestimates cooling. The law also assumes the ambient temperature stays constant and the object has a uniform internal temperature (low Biot number).

Can I use this for warming as well as cooling?

Yes. If the initial temperature is below the ambient temperature (for example, a cold drink in a warm room), T0 - T_amb is negative and the formula still applies: the temperature rises exponentially toward ambient rather than falling. The cooling constant k and all formulas remain identical.

Sources

Written by Dr. Tomás Okafor, PhD Physicist · Lagos, Nigeria

Physicist specializing in classical mechanics, bringing 17 years of research and applied dynamics expertise to every calculator he reviews.

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